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CIE 9709 2026 June Paper 15 Q6

A Level / CIE / P1

CIE 9709 2026 June Paper 15 Paper · Question 6

题目

Problem

Find the set of values of kk for which the line y+4x=ky+4x=k and the curve with equation y=4−7x−2x2y=4-7x-2x^2 have at least one point of intersection.

(4)
题目中文翻译

求使直线 y+4x=ky+4x=k 与曲线 y=4−7x−2x2y=4-7x-2x^2 至少有一个交点的 kk 的取值集合。

(4)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

解法一

思路

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把两条曲线的 yy 写成相同的式子,得到关于 xx 的二次方程。至少一个交点等价于判别式非负。

答题过程

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At an intersection,

k−4x=4−7x−2x2⟺2x2+3x+k−4=0.k-4x=4-7x-2x^2 \quad\Longleftrightarrow\quad 2x^2+3x+k-4=0.

There is at least one real root if and only if 32−8(k−4)=41−8k≥03^2-8(k-4)=41-8k\ge0. Thus k≤41/8k\le41/8, with equality giving a single intersection.

解法二

思路

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也可以把曲线上的 y+4xy+4x 配方。直线能与曲线相交的 kk 正是这个表达式能取到的值。

答题过程

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On the curve,

y+4x=4−3x−2x2=418−2(x+34)2.y+4x=4-3x-2x^2=\frac{41}{8}-2\Big(x+\frac34\Big)^2.

This expression takes every value in (−∞,41/8](-\infty,41/8]. Thus an intersection exists exactly when k≤41/8k\le41/8.