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CIE 9709 2022 November Paper 11 Q1

A Level / CIE / P1

CIE 9709 2022 Nov Paper 11 Paper · Question 1

题目

Problem

Solve the equation 3x+2=2x−13x+2=\dfrac{2}{x-1}.

(3)
题目中文翻译

解方程 3x+2=2x−13x+2=\dfrac{2}{x-1}。

(3)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

解法一

思路

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先记录分母的限制,再乘以 x−1x-1 化为二次方程。

答题过程

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The equation requires x≠1x\ne1. Multiplying by x−1x-1 gives (3x+2)(x−1)=2(3x+2)(x-1)=2, so

3x2−x−4=(x+1)(3x−4)=0.3x^2-x-4=(x+1)(3x-4)=0.

Thus x=−1x=-1 or 4/34/3. Both satisfy the restriction and the original equation.