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CIE 9709 2022 November Paper 13 Q8

A Level / CIE / P1

CIE 9709 2022 Nov Paper 13 Paper · Question 8

题目

Problem

The diagram shows two identical circles intersecting at points AA and BB and with centres at PP and QQ. The radius of each circle is rr and the distance PQPQ is 53r\dfrac{5}{3}r.

(a) Find the perimeter of the shaded region in terms of rr.

(4)

(b) Find the area of the shaded region in terms of rr.

(3)
题目中文翻译

图中两个相同的圆相交于点 AA 和 BB,圆心分别为 PP 和 QQ。每个圆的半径为 rr,距离 PQPQ 为 53r\dfrac{5}{3}r。

(a) 用 rr 表示阴影区域的周长。

(4)

(b) 用 rr 表示阴影区域的面积。

(3)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

(a)

解法一

思路

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两圆半径相同,公共弦与两圆心连线垂直且通过其中点。用半个圆心距求每段弧的圆心角。

答题过程

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Let MM be the midpoint of PQPQ, where the common chord meets PQPQ. Then PM=5r/6PM=5r/6 and PA=rPA=r. Hence the half-angle is β=arccos⁡(5/6)=0.5856855434…\beta=\arccos(5/6)=0.5856855434\ldots radians. Each of the two arcs subtends 2β2\beta, so the perimeter is

4rarccos⁡56≈2.34r.4r\arccos\frac56\approx2.34r.

(b)

解法一

思路

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阴影由两个全等弓形组成。每个弓形的面积是圆心角为 2β2\beta 的扇形减去三角形。

答题过程

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Using β=arccos⁡(5/6)\beta=\arccos(5/6) from (a), the area is

 2(12r2(2β)−12r2sin⁡(2β))= r2(2β−sin⁡(2β)) ≈0.250r2.\begin{align*} &\,2\Big(\frac12r^2(2\beta)-\frac12r^2\sin(2\beta)\Big)\\ =&\,r^2(2\beta-\sin(2\beta))\\ &\,\approx0.250r^2. \end{align*}