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CIE 9709 2023 November Paper 13 Q1

A Level / CIE / P1

CIE 9709 2023 Nov Paper 13 Paper · Question 1

题目

Problem

A curve is such that its gradient at a point (x,y)(x,y) is given by dydx=x−3x−12\dfrac{\mathrm{d}y}{\mathrm{d}x}=x-3x^{-\frac{1}{2}}. It is given that the curve passes through the point (4,1)(4,1).

Find the equation of the curve.

(4)
题目中文翻译

一条曲线在点 (x,y)(x,y) 处的斜率为 dydx=x−3x−12\dfrac{\mathrm{d}y}{\mathrm{d}x}=x-3x^{-\frac{1}{2}}。已知曲线经过点 (4,1)(4,1)。

求曲线的方程。

(4)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

解法一

思路

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对两个幂函数分别积分,再代入已知点求常数。

答题过程

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Integrating gives

y=x22−6x+C.y=\frac{x^2}{2}-6\sqrt x+C.

At (4,1)(4,1) this is 1=8−12+C1=8-12+C, so C=5C=5. The curve is y=x2/2−6x+5y=x^2/2-6\sqrt x+5 for x>0x>0.