题目
Problem
A function f with domain x>0 is such that f′(x)=8(2x−3)31−10x32. It is given that the curve with equation y=f(x) passes through the point (1,0).
(a) Find the equation of the normal to the curve at the point (1,0).
[3]
(b) Find f(x).
[4]
It is given that the equation f′(x)=0 can be expressed in the form
125x2−128x+192=0.
(c) Determine, making your reasoning clear, whether f is an increasing function, a decreasing function or neither.
[3]
题目中文翻译
函数 f 的定义域为 x>0,且 f′(x)=8(2x−3)31−10x32。已知方程为 y=f(x) 的曲线经过点 (1,0)。
(a) 求曲线在点 (1,0) 处的法线方程。
(b) 求 f(x)。
已知方程 f′(x)=0 可以表示为
125x2−128x+192=0.
(c) 判断 f 是增函数、减函数还是都不是,并清楚说明理由。
解答