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CIE 9709 2024 November Paper 12 Q6

A Level / CIE / P1

CIE 9709 2024 Nov Paper 12 Paper · Question 6

题目

Problem

The diagram shows a metal plate OABCDEFOABCDEF consisting of sectors of two circles, each with centre OO. The radii of sectors AOBAOB and EOFEOF are rr cm and the radius of sector CODCOD is 2r2r cm. Angle AOB=AOB= angle EOF=θEOF=\theta radians and angle COD=2θCOD=2\theta radians.

It is given that the perimeter of the plate is 1414 cm and the area of the plate is 10 cm210\text{ cm}^2.

Given that r>32r>\dfrac{3}{2} and θ<34\theta<\dfrac{3}{4}, find the values of rr and θ\theta.

[6]
题目中文翻译

图中显示一块金属板 OABCDEFOABCDEF,它由两个以 OO 为圆心的圆的扇形组成。扇形 AOBAOBEOFEOF 的半径为 rr cm,扇形 CODCOD 的半径为 2r2r cm。角 AOB=AOB=EOF=θEOF=\theta 弧度,角 COD=2θCOD=2\theta 弧度。

已知这块板的周长为 1414 cm,面积为 10 cm210\text{ cm}^2

已知 r>32r>\dfrac{3}{2}θ<34\theta<\dfrac{3}{4},求 rrθ\theta 的值。

解答