Skip to content
CalcGospel 國際數學圖譜
返回

CIE 9709 2024 November Paper 13 Q11

A Level / CIE / P1

CIE 9709 2024 Nov Paper 13 Paper · Question 11

题目

Problem

The equation of a curve is y=kx124x2+2y = kx^{\frac{1}{2}} - 4x^2 + 2, where kk is a constant.

(a) Find dydx\frac{dy}{dx} and d2ydx2\frac{d^2y}{dx^2} in terms of kk.

[2]

(b) It is given that k=2k = 2.

Find the coordinates of the stationary point and determine its nature.

[4]

(c) Points AA and BB on the curve have xx-coordinates 0.25 and 1 respectively. For a different value of kk, the tangents to the curve at the points AA and BB meet at a point with xx-coordinate 0.6.

Find this value of kk.

[6]
题目中文翻译

一条曲线的方程为 y=kx124x2+2y = kx^{\frac{1}{2}} - 4x^2 + 2,其中 kk 是常数。

(a) 用 kk 表示 dydx\frac{dy}{dx}d2ydx2\frac{d^2y}{dx^2}

(b) 已知 k=2k = 2

求驻点的坐标,并判断其性质。

(c) 曲线上的点 AABBxx 坐标分别为 0.25 和 1。对于另一个 kk 的值,曲线在 AABB 点处的切线相交于一个 xx 坐标为 0.6 的点。

求这个 kk 的值。

解答