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CIE 9709 2025 Nov Paper 11 Q2

A Level / CIE / P1

CIE 9709 2025 Nov Paper 11 Paper · Question 2

题目

Problem

A geometric progression has first term aa and common ratio cos⁡θ\cos\theta, where 0<θ<12π0<\theta<\frac{1}{2}\pi. It is given that the second term is 8 and the fifth term is 18\frac{1}{8}.

(a) Find the value of θ\theta. Give your answer correct to 3 significant figures.

[3]

(b) Find the exact value of the sum to infinity.

[2]
题目中文翻译

一个等比数列的首项为 aa,公比为 cos⁡θ\cos\theta,其中 0<θ<12π0<\theta<\frac{1}{2}\pi。已知第二项为 8,第五项为 18\frac{1}{8}。

(a) 求 θ\theta 的值,答案精确到 3 位有效数字。

(b) 求无穷和的精确值。

解答

(a)

解法一

思路

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第五项比第二项多乘三次公比。用两项相除消去首项,再用反余弦求角。

答题过程

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Let r=cos⁡θr=\cos\theta. Since the second and fifth terms are ar=8ar=8 and ar4=18ar^4=\frac18,

r3=1/88=164,r=14.r^3=\frac{1/8}{8}=\frac1{64},\qquad r=\frac14.

As 0<θ<π20<\theta<\frac\pi2, the solution is θ=cos⁡−1(14)≈1.32\theta=\cos^{-1}(\frac14)\approx1.32 radians to three significant figures.

(b)

解法一

思路

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沿用 (a) 的精确公比,用第二项求首项。公比的绝对值小于 11,所以可以求无穷和。

答题过程

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From ar=8ar=8 and r=14r=\frac14, the first term is a=32a=32. Since ∣r∣<1|r|<1, the exact sum to infinity is

S∞=321−1/4=1283.S_\infty=\frac{32}{1-1/4}=\frac{128}{3}.