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CIE 9709 2025 Nov Paper 12 Q3

A Level / CIE / P1

CIE 9709 2025 Nov Paper 12 Paper · Question 3

题目

Problem

(a) The graph of y=f(x)y=f(x) is transformed to the graph of y=f(3x)+2y=f(3x)+2.

Describe fully the two transformations which have been combined to give the resulting graph.

[3]

(b) A different graph has equation y=g(x)y=g(x). This graph is stretched by scale factor 3 in the yy-direction and then reflected in the yy-axis.

Write down the equation of the transformed graph in terms of the function gg.

[2]
题目中文翻译

(a) y=f(x)y=f(x) 的图像被变换为 y=f(3x)+2y=f(3x)+2 的图像。

完整描述组合后得到该图像的两个变换。

(b) 另一条图像的方程为 y=g(x)y=g(x)。该图像在 yy 方向上按比例因子 3 拉伸,然后关于 yy 轴反射。

用函数 gg 写出变换后图像的方程。

解答

(a)

解法一

思路

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追踪原图上一点 (u,f(u))(u,f(u))。输入要等于 uu,所以新横坐标是 u/3u/3;外面的 +2+2 则改变纵坐标。

答题过程

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A point (u,f(u))(u,f(u)) maps to (u/3,f(u)+2)(u/3,f(u)+2). The transformations are a stretch of scale factor 13\frac13 in the xx-direction and a translation by the vector (02)\begin{pmatrix}0\\2\end{pmatrix}.

(b)

解法一

思路

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竖直伸缩改变函数值,关于 yy 轴反射改变横坐标的符号。

答题过程

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The vertical stretch gives y=3g(x)y=3g(x). Reflection in the yy-axis replaces xx with −x-x, so the transformed graph is y=3g(−x)y=3g(-x).