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CIE 9709 2025 Nov Paper 12 Q8

A Level / CIE / P1

CIE 9709 2025 Nov Paper 12 Paper · Question 8

题目

Problem

The first three terms of a geometric progression are aa, bb and cc respectively, where aa, bb and cc are positive constants. The first three terms of an arithmetic progression are aa, bb and 3c-3c respectively.

(a) Show that a210ac+9c2=0a^2-10ac+9c^2=0.

[3]

It is now given that a=9a=9 and cc takes the smaller of its two possible values.

(b) (i) Find the sum to infinity of the geometric progression.

[5]

(ii) Find the sum of the first 20 terms of the arithmetic progression.

[3]
题目中文翻译

一个等比数列的前三项分别为 aabbcc,其中 aabbcc 是正常数。一个等差数列的前三项分别为 aabb3c-3c

(a) 证明 a210ac+9c2=0a^2-10ac+9c^2=0

现在给定 a=9a=9,并且 cc 取两个可能值中较小的一个。

(b) (i) 求该等比数列的无穷和。

(ii) 求该等差数列前 20 项的和。

解答