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CIE 9709 2025 Nov Paper 13 Q1

A Level / CIE / P1

CIE 9709 2025 Nov Paper 13 Paper · Question 1

题目

Problem

(a) Expand (212x)6\left(2-\frac{1}{2}x\right)^6 in ascending powers of xx up to and including the term in x3x^3.

[3]

(b) Hence find the coefficient of x3x^3 in the expansion of (3x+2x3)(212x)6\left(3-x+2x^3\right)\left(2-\frac{1}{2}x\right)^6.

[2]
题目中文翻译

(a) 将 (212x)6\left(2-\frac{1}{2}x\right)^6xx 的升幂展开,直到并包括 x3x^3 项。

(b) 由此,求 (3x+2x3)(212x)6\left(3-x+2x^3\right)\left(2-\frac{1}{2}x\right)^6 展开式中 x3x^3 的系数。

解答