题目
Problem
(a) Find the quotient and remainder when 8x3+4x2+2x+7 is divided by 4x2+1.
(3)
(b) Hence find the exact value of
∫0214x2+18x3+4x2+2x+7dx.
(5)
题目中文翻译
(a) 求 8x3+4x2+2x+7 除以 4x2+1 的商和余数。
(3)
(b) 由此求
∫0214x2+18x3+4x2+2x+7dx
的精确值。
(5)
原卷通用作答要求
Answer all questions. You should use a calculator where appropriate.
You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.
Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.
请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。
解答
(a)
解法一
思路
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依次除最高次项,再减去对应倍数的除式,剩下常数余式。
答题过程
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Subtracting 2x(4x2+1),
(8x3+4x2+2x+7)−2x(4x2+1)=4x2+7.
Subtracting one more copy of the divisor gives
(4x2+7)−(4x2+1)=6.
Therefore
8x3+4x2+2x+7=(4x2+1)(2x+1)+6.
The quotient is 2x+1 and the remainder is 6.
(b)
解法一
思路
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承接(a),将被积函数写成一次多项式加反正切型分式,逐项积分。
答题过程
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Using part (a),
4x2+18x3+4x2+2x+7=2x+1+4x2+16.
Since dxdtan−1(2x)=2/(1+4x2), the remaining integral is 3tan−1(2x). Thus
I===[x2+x+3tan−1(2x)]01/241+21+43π43(1+π).