题目
Problem
The diagram shows the curve y=x3lnx, for x>0, and its minimum point M.
(a) Find the exact coordinates of M.
(4)
(b) Find the exact area of the shaded region bounded by the curve, the x-axis and the line x=21.
(5)
题目中文翻译
图中显示了曲线 y=x3lnx(x>0)及其最小值点 M。
(a) 求 M 的精确坐标。
(4)
(b) 求曲线、x 轴及直线 x=21 所围成的阴影区域的精确面积。
(5)
原卷通用作答要求
Answer all questions. You should use a calculator where appropriate.
You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.
Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.
请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。
解答
(a)
解法一
思路
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用乘积法则求导,注意 x>0,所以 x2 不能为零。解出对数条件后代回求纵坐标。
答题过程
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Differentiating,
dxdy==3x2lnx+x3x1x2(3lnx+1).
Since x>0, the stationary point satisfies
3lnx+1=0,x=e−1/3.
The derivative changes from negative to positive at this value, so it is a minimum. Substituting,
y=(e−1/3)3ln(e−1/3)=e−1(−31)=−3e1.
Thus
M=(e−1/3,−3e1).
(b)
解法一
思路
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曲线在 1/2≤x≤1 位于横轴下方,面积是负积分。用分部积分处理 x3lnx,再取相反数。
答题过程
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The curve meets the x-axis at x=1. On 1/2≤x≤1, x3lnx≤0, so
A=−∫1/21x3lnxdx.
Integrating by parts with u=lnx, dv=x3dx,
∫x3lnxdx==4x4lnx−41∫x3dx4x4lnx−16x4+C.
Thus
A===−[4x4lnx−16x4]1/21−[−161−(−64ln2−2561)]25615−64ln2.