题目
By first expressing the equation as a quadratic equation in , solve the equation for .
题目中文翻译
先将方程 表示为关于 的一元二次方程,再解此方程,其中 。
原卷通用作答要求
Answer all questions. You should use a calculator where appropriate.
You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.
Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.
请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。
解答
解法一
思路
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按题意先化成正切的二次方程。解出两个正切值后,要在第二象限补回负正切值所对应的角。
答题过程
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The original equation excludes and .
Using the tangent subtraction formula and writing ,
The value , where is undefined, is not a solution of the original equation. For the remaining allowed angles, multiplying through gives
Hence
Solving,
The positive root gives . The negative root gives a second-quadrant angle . Both are defined in the original equation.
Thus