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CIE 9709 2022 June Paper 33 Q1

A Level / CIE / P3

CIE 9709 2022 June Paper 33 Paper · Question 1

题目

Problem

Find, in terms of aa, the set of values of xx satisfying the inequality

2∣3x+a∣<∣2x+3a∣,2|3x+a|<|2x+3a|,

where aa is a positive constant.

(4)
题目中文翻译

求满足不等式

2∣3x+a∣<∣2x+3a∣2|3x+a|<|2x+3a|

的 xx 的取值集合,用 aa 表示,其中 aa 为正常数。

(4)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

解法一

思路

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两边非负,可以等价平方。整理并因式分解后,利用 a>0a>0 确定两个根的大小顺序。

答题过程

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Squaring both non-negative sides gives

4(3x+a)2<(2x+3a)2.4(3x+a)^2<(2x+3a)^2.

Hence

36x2+24ax+4a2< 4x2+12ax+9a2,32x2+12ax−5a2< 0,(8x+5a)(4x−a)< 0.\begin{align*} 36x^2+24ax+4a^2<&\,4x^2+12ax+9a^2,\\[4mm] 32x^2+12ax-5a^2<&\,0,\\[4mm] (8x+5a)(4x-a)<&\,0. \end{align*}

Since a>0a>0, the roots are ordered as −5a/8<a/4-5a/8<a/4. The product is negative between them, so

−5a8<x<a4.\boxed{-\frac{5a}{8}<x<\frac a4}.