Skip to content
CalcGospel 國際數學圖譜
返回

CIE 9709 2023 June Paper 32 Q3

A Level / CIE / P3

CIE 9709 2023 June Paper 32 Paper · Question 3

题目

Problem

(a) On an Argand diagram, sketch the locus of points representing complex numbers zz satisfying ∣z+3−2i∣=2|z+3-2\mathrm{i}|=2.

(2)

(b) Find the least value of ∣z∣|z| for points on this locus, giving your answer in an exact form.

(2)
题目中文翻译

(a) 在阿尔冈图上,画出表示满足 ∣z+3−2i∣=2|z+3-2\mathrm{i}|=2 的复数 zz 的点的轨迹草图。

(2)

(b) 求此轨迹上的点所对应的 ∣z∣|z| 的最小值,答案用精确形式表示。

(2)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

(a)

解法一

思路

展开

模等于常数表示圆周,注意复数中心的实部为 −3-3、虚部为 22,不是把原式中的符号直接照抄。

答题过程

展开

The locus is the circle

(x+3)2+(y−2)2=4,(x+3)^2+(y-2)^2=4,

with centre (−3,2)(-3,2) and radius 22. It is tangent to the real axis at (−3,0)(-3,0).

Sketch the circumference only, with the centre and radius indicated.

(b)

解法一

思路

展开

原点到圆心的距离大于半径。沿圆心与原点连线取靠近原点的圆上点,就得到最短距离。

答题过程

展开

Let C=(−3,2)C=(-3,2) be the centre. Then

OC=(−3)2+22=13>2.OC=\sqrt{(-3)^2+2^2}=\sqrt{13}>2.

The nearest point on the circle to the origin lies on the segment from OO to CC, at distance 22 from CC. Therefore

min⁡∣z∣=OC−2=13−2.\boxed{\min|z|=OC-2=\sqrt{13}-2}.