题目
Problem
The parametric equations of a curve are
x=2−sinθcosθ,y=θ+2cosθ.
Show that dxdy=(2−sinθ)2.
(5)
题目中文翻译
一条曲线的参数方程为
x=2−sinθcosθ,y=θ+2cosθ.
证明 dxdy=(2−sinθ)2。
(5)
原卷通用作答要求
Answer all questions. You should use a calculator where appropriate.
You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.
Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.
请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。
解答
解法一
思路
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分别对参数求导。求 x 的导数时用商法则,再用 sin2θ+cos2θ=1 合并分子,最后取两导数之比。
答题过程
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Differentiating y=θ+2cosθ,
dθdy=1−2sinθ.
By the quotient rule,
dθdx===(2−sinθ)2−(2−sinθ)sinθ+cos2θ(2−sinθ)2−2sinθ+sin2θ+cos2θ(2−sinθ)21−2sinθ.
At regular parameter values, where 1−2sinθ=0,
dxdy==dx/dθdy/dθ(1−2sinθ)/(2−sinθ)21−2sinθ.
Hence
dxdy=(2−sinθ)2.
When sinθ=1/2, both parameter derivatives vanish; the tangent-gradient limit from nearby regular points is (3/2)2=9/4.