题目
The diagram shows the part of the curve for , and its maximum point , where .
(a) Show that satisfies the equation .
(b) Use an iterative formula based on the equation in (a) to determine correct to decimal places. Give the result of each iteration to decimal places.
题目中文翻译
图中显示了曲线 在 范围内的部分,以及其最大值点 ,该点处 。
(a) 证明 满足方程 。
(b) 使用基于 (a) 问方程的迭代公式求 ,结果保留 位小数。每次迭代的结果保留 位小数。
原卷通用作答要求
Answer all questions. You should use a calculator where appropriate.
You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.
Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.
请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。
解答
(a)
解法一
思路
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最高点位于区间内部,导数为零。先约去非零的 与 ,再取反正切;用 确定分支。
答题过程
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Differentiating,
At the interior maximum ,
Since , both and are non-zero. Dividing gives
Also , so
(b)
解法一
思路
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用(a)给出的式子迭代,角度用弧度,内部保留精度,列表到四位小数。
答题过程
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Use
The successive values are:
| to 4 decimal places | |
|---|---|
| 0 | 0.4000 |
| 1 | 0.3435 |
| 2 | 0.3650 |
| 3 | 0.3566 |
| 4 | 0.3599 |
| 5 | 0.3586 |
| 6 | 0.3591 |
| 7 | 0.3589 |
| 8 | 0.3590 |
| 9 | 0.3590 |
Hence to 2 decimal places.