(a) 画出 $y=|x-2a|$ 的图像草图，其中 $a$ 为正常数。

(b) 解不等式 $2x-3a<|x-2a|$。

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程；仅给出计算器答案而没有过程，不予评分。除非题目另有精度要求，非精确数值答案保留 3 位有效数字，以度为单位的角度保留 1 位小数。

绝对值图像的顶点和纵截距都由参数 $a$ 表示，不要把参数自行取成数值。

The graph is V-shaped, with vertex $(2a,0)$ and $y$-intercept $(0,2a)$.

Draw solid straight branches $y=2a-x$ for $x<2a$ and $y=x-2a$ for $x\geqslant2a$, extending into negative $x$ as well.

按绝对值内部的符号分段，第二段的解要与该段定义范围取交集。

For $x<2a$,

Thus $x<5a/3$, which is consistent with this branch since $a>0$.

For $x\geqslant2a$,

This is incompatible with $x\geqslant2a$. Hence