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CIE 9709 2024 June Paper 33 Q1

A Level / CIE / P3

CIE 9709 2024 June Paper 33 Paper · Question 1

题目

Problem

Solve the equation 83−6x=4×5−2x8^{3-6x}=4\times5^{-2x}. Give your answer correct to 33 decimal places.

(4)
题目中文翻译

解方程 83−6x=4×5−2x8^{3-6x}=4\times5^{-2x}。答案保留 33 位小数。

(4)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

解法一

思路

展开

先取自然对数,再用幂的对数法则把指数中的 xx 移到乘数位置,整理为一次方程。

答题过程

展开

Taking natural logarithms,

(3−6x)ln⁡8= ln⁡4−2xln⁡5,3ln⁡8−ln⁡4= x(6ln⁡8−2ln⁡5).\begin{align*} (3-6x)\ln8=&\,\ln4-2x\ln5,\\[4mm] 3\ln8-\ln4=&\,x(6\ln8-2\ln5). \end{align*}

Hence

x= 3ln⁡8−ln⁡46ln⁡8−2ln⁡5= 0.524103….\begin{align*} x=&\,\frac{3\ln8-\ln4}{6\ln8-2\ln5}\\[4mm] =&\,0.524103\ldots. \end{align*}

Therefore x=0.524\boxed{x=0.524}, to 3 decimal places.

解法二

思路

展开

先把所有含 xx 的指数合并到同一个底数,再取对数,可减少对数展开。

答题过程

展开

Using the laws of indices,

83 8−6x= 4 5−2x,128= (835)2x.\begin{align*} 8^3\,8^{-6x}=&\,4\,5^{-2x},\\[4mm] 128=&\,\bigg(\frac{8^3}{5}\bigg)^{2x}. \end{align*}

Taking natural logarithms gives

ln⁡128=2xln⁡(5125).\ln128=2x\ln\bigg(\frac{512}{5}\bigg).

Thus

x=ln⁡1282ln⁡(512/5)≈0.524x=\frac{\ln128}{2\ln(512/5)}\approx\boxed{0.524}

to 3 decimal places.