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CIE 9709 2025 June Paper 31 Q1

A Level / CIE / P3

CIE 9709 2025 June Paper 31 Paper · Question 1

题目

Problem

(a) Sketch the graph of y=∣2x−3∣y=|2x-3|.

(1)

(b) Solve the inequality 3x−1<∣2x−3∣3x-1<|2x-3|.

(2)
题目中文翻译

(a) 画出 y=∣2x−3∣y=|2x-3| 的图像的草图。

(1)

(b) 解不等式 3x−1<∣2x−3∣3x-1<|2x-3|。

(2)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

(a)

解法一

思路

展开

画绝对值的两条直线分支,标出顶点和纵轴截距。

答题过程

展开

The graph is V-shaped, with vertex (3/2,0)(3/2,0) and yy-intercept (0,3)(0,3).

Draw y=3−2xy=3-2x for x<3/2x<3/2 and y=2x−3y=2x-3 for x⩾3/2x\geqslant3/2, with both branches solid and extending upwards.

(b)

解法一

思路

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按绝对值内部的符号分段,解出的条件还要符合本段范围。

答题过程

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If x<3/2x<3/2,

3x−1<3−2x⟹5x<4,3x-1<3-2x \quad\Longrightarrow\quad 5x<4,

so x<4/5x<4/5, which is within this branch.

If x⩾3/2x\geqslant3/2,

3x−1<2x−3⟹x<−2.3x-1<2x-3 \quad\Longrightarrow\quad x<-2.

This is incompatible with x⩾3/2x\geqslant3/2. Hence

x<45.\boxed{x<\frac45}.