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CIE 9709 2025 June Paper 32 Q3

A Level / CIE / P3

CIE 9709 2025 June Paper 32 Paper · Question 3

题目

Problem

On an Argand diagram shade the region whose points represent complex numbers zz which satisfy both the inequalities ∣z−3i∣≤2|z-3\mathrm{i}|\le2 and 14π≤arg⁡(z−1−2i)≤34π\frac14\pi\le\arg(z-1-2\mathrm{i})\le\frac34\pi.

(5)
题目中文翻译

在 Argand 图上用阴影标出一个区域,使其中的点表示同时满足不等式 ∣z−3i∣≤2|z-3\mathrm{i}|\le2 和 14π≤arg⁡(z−1−2i)≤34π\frac14\pi\le\arg(z-1-2\mathrm{i})\le\frac34\pi 的复数 zz。

(5)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

解法一

思路

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先画圆盘,再以平移后的点为顶点画辐角扇形。辐角在顶点没有定义,因此即使两条射线包括边界,顶点本身仍应排除。

答题过程

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The inequality ∣z−3i∣⩽2|z-3\mathrm{i}|\leqslant2 represents the closed disk with centre (0,3)(0,3) and radius 22.

The argument is measured from P=(1,2)P=(1,2), since z−1−2i=z−(1+2i)z-1-2\mathrm{i}=z-(1+2\mathrm{i}). Draw rays from PP at angles π/4\pi/4 and 3π/43\pi/4 to the positive real direction.

Writing z=x+yiz=x+y\mathrm{i}, the sector is

y−2⩾∣x−1∣,z≠1+2i.y-2\geqslant|x-1|,\qquad z\ne1+2\mathrm{i}.

Shade the intersection of this upward sector with the disk. Include the circular and ray boundaries where defined, but mark PP as excluded because arg⁡0\arg0 is undefined.