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CIE 9709 2025 June Paper 35 Q1

A Level / CIE / P3

CIE 9709 2025 June Paper 35 Paper · Question 1

题目

Problem

Solve the equation 34−2x=5(6x−1)3^{4-2x}=5(6^{x-1}). Give your answer correct to 33 significant figures.

(4)
题目中文翻译

解方程 34−2x=5(6x−1)3^{4-2x}=5(6^{x-1})。答案保留 33 位有效数字。

(4)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

解法一

思路

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取对数后,把指数移到系数位置,再收集所有含 xx 的项。

答题过程

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Taking natural logarithms,

(4−2x)ln⁡3=ln⁡5+(x−1)ln⁡6.(4-2x)\ln3=\ln5+(x-1)\ln6.

Collecting terms,

x(2ln⁡3+ln⁡6)=4ln⁡3+ln⁡6−ln⁡5.x(2\ln3+\ln6)=4\ln3+\ln6-\ln5.

Thus

x= 4ln⁡3+ln⁡6−ln⁡52ln⁡3+ln⁡6= 1.147352…=1.15.\begin{align*} x=&\,\frac{4\ln3+\ln6-\ln5}{2\ln3+\ln6}\\[4mm] =&\,1.147352\ldots=\boxed{1.15}. \end{align*}