题目
Problem
Solve the equation 3cotθ−4cosec2θ+5=0 for −π≤θ≤π.
(5)
题目中文翻译
解方程 3cotθ−4cosec2θ+5=0,其中 −π≤θ≤π。
(5)
原卷通用作答要求
Answer all questions. You should use a calculator where appropriate.
You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.
Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.
请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。
解答
解法一
思路
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用余割与余切的平方关系化为二次方程,逐个列出指定区间内的角。
答题过程
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Using cosec2θ=1+cot2θ,
3cotθ−4(1+cot2θ)+5=0,
so
4cot2θ−3cotθ−1=0.
Factoring,
(4cotθ+1)(cotθ−1)=0.
For cotθ=1, the solutions in [−π,π] are θ=π/4 and θ=−3π/4.
For cotθ=−1/4, tanθ=−4, giving
θ=−tan−14=−1.325817…
and
θ=π−tan−14=1.815774….
Therefore
θ=−43π, −1.33, 4π, 1.82.
The values −π,0,π are excluded because the original cotangent and cosecant are undefined there.