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CIE 9709 2024 November Paper 33 Q1

A Level / CIE / P3

CIE 9709 2024 Nov Paper 33 Paper · Question 1

题目

Problem

The complex number zz satisfies ∣z∣=2|z|=2 and 0≤arg⁡z≤14π0\le\arg z\le\frac14\pi.

(a) On the Argand diagram below, sketch the locus of the points representing zz.

(2)

(b) On the same diagram, sketch the locus of the points representing z2z^2.

(2)

题目中文翻译

复数 zz 满足 ∣z∣=2|z|=2 且 0≤arg⁡z≤14π0\le\arg z\le\frac14\pi。

(a) 在下方的 Argand 图中,画出表示 zz 的点的轨迹草图。

(2)

(b) 在同一个图中,画出表示 z2z^2 的点的轨迹草图。

(2)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

(a)

解法一

思路

展开

固定模长给出圆,辐角区间选出第一象限的一段圆弧。这里画弧线,不涂扇形内部。

答题过程

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The locus is the arc of the circle with centre OO and radius 22, from argument 00 to argument π/4\pi/4.

Its endpoints are (2,0)(2,0) and (2,2)(\sqrt2,\sqrt2), both included. Draw the arc without shading the sector. The combined diagram is shown in (b).

(b)

解法一

思路

展开

平方把模长变为原来的平方,辐角加倍。因此较小角范围变成第一象限的整个四分之一圆。

答题过程

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Write z=2eiθz=2e^{\mathrm{i}\theta}, where 0⩽θ⩽π/40\leqslant\theta\leqslant\pi/4. Then

z2= 4e2iθ, 0⩽2θ⩽π/2.\begin{align*} z^2=&\,4e^{2\mathrm{i}\theta},\\[4mm] &\,0\leqslant2\theta\leqslant\pi/2. \end{align*}

On the same diagram, draw the first-quadrant quarter-circle arc with centre OO and radius 44, from (4,0)(4,0) to (0,4)(0,4), including both endpoints.

Show both arcs clearly and do not shade their interiors.