题目
Problem
Find the exact value of ∫01xtan−1xdx.
(6)
题目中文翻译
求 ∫01xtan−1xdx 的精确值。
(6)
原卷通用作答要求
Answer all questions. You should use a calculator where appropriate.
You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.
Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.
请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。
解答
解法一
思路
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分部积分时对反正切求导、对 x 积分。余下分式先拆成一与简单分式,再积分。
答题过程
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Let u=tan−1x and dv=xdx. Integration by parts gives
I====[2x2tan−1x]01−21∫011+x2x2dx8π−21∫01(1−1+x21)dx8π−21[x−tan−1x]018π−21(1−4π).
The lower-limit contributions are zero because x=0 and tan−10=0. Hence
I=4π−21.