题目
Find the quotient and the remainder when is divided by .
题目中文翻译
求 除以 所得的商和余数。
原卷通用作答要求
Answer all questions. You should use a calculator where appropriate.
You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.
Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.
请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。
解答
解法一
思路
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补上缺失项的零系数后做综合除法,除数 对应使用 。
答题过程
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Dividing by , use the synthetic value and coefficients :
| Step | Leading coefficient | Next coefficient calculation |
|---|---|---|
| 1 | ||
| 2 | ||
| 3 | ||
| 4 |
Thus
The quotient is and the remainder is .
解法二
思路
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先用余式定理求常数余式,再对商设一般形式并比较系数。
答题过程
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Let . By the remainder theorem, the remainder is
Write
Comparing coefficients gives
Therefore , , , . The constant coefficient checks since .
Hence the quotient is and the remainder is .