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CIE 9709 2023 March Paper 52 Q4

A Level / CIE / S1

CIE 9709 2023 March Paper 52 Paper · Question 4

题目

Problem

The probability that it will rain on any given day is xx. If it is raining, the probability that Aran wears a hat is 0.8 and if it is not raining, the probability that he wears a hat is 0.3. Whether it is raining or not, if Aran wears a hat, the probability that he wears a scarf is 0.4. If he does not wear a hat, the probability that he wears a scarf is 0.1. The probability that on a randomly chosen day it is not raining and Aran is not wearing a hat or a scarf is 0.36.

Find the value of xx.

(3)

题目中文翻译

任意一天下雨的概率为 xx。若下雨,Aran 戴帽子的概率为 0.8;若不下雨,他戴帽子的概率为 0.3。无论是否下雨,若 Aran 戴帽子,他戴围巾的概率为 0.4;若他不戴帽子,他戴围巾的概率为 0.1。随机选择一天,当天不下雨且 Aran 既不戴帽子也不戴围巾的概率为 0.36。

求 xx 的值。

(3)

原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

解法一

思路

展开

不下雨、不戴帽、不戴围巾是一条连续条件路径,分别取补概率。

答题过程

展开  P(no rain, no hat, no scarf)= (1−x)(0.7)(0.9)=0.36.\begin{align*} &\,\mathrm{P}(\text{no rain, no hat, no scarf})\\[4mm] =&\,(1-x)(0.7)(0.9)=0.36. \end{align*}

Thus

1−x=0.360.63=47,x=37.1-x=\frac{0.36}{0.63}=\frac47, \qquad x=\boxed{\frac37}.