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CIE 9709 2025 June Paper 55 Q1

A Level / CIE / S1

CIE 9709 2025 June Paper 55 Paper · Question 1

题目

Problem

Two fair 6-sided dice with faces labelled 1, 2, 3, 4, 5, 6 are thrown. The two scores are noted. The random variable XX is defined as follows.

  • If the two scores are equal, X=0X=0
  • If the scores are not equal, XX is the larger score minus the smaller score

(a) Draw up the probability distribution table for XX.

(3)

(b) Find E(X)\mathrm{E}(X) and Var⁡(X)\operatorname{Var}(X).

(3)
题目中文翻译

掷两枚均匀的六面骰子,每枚骰子的各面分别标有 1、2、3、4、5、6。记下两个点数。随机变量 XX 定义如下。

  • 如果两个点数相等,则 X=0X=0
  • 如果两个点数不相等,则 XX 为较大的点数减去较小的点数

(a) 列出 XX 的概率分布表。

(3)

(b) 求 E(X)\mathrm{E}(X) 和 Var⁡(X)\operatorname{Var}(X)。

(3)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

(a)

解法一

思路

展开

两骰有36个等可能有序结果。差为0有6个;正差为x时,较小数可从1选到6减x,且两骰次序可交换。

答题过程

展开

There are 36 equally likely ordered outcomes. For X=0X=0, the scores must be equal, giving six outcomes.

For x=1,2,3,4,5x=1,2,3,4,5, choose the smaller score in 6−x6-x ways and choose which die shows it in two ways. Thus P(X=x)=2(6−x)36\mathrm{P}(X=x)=\frac{2(6-x)}{36}.

xx001122334455
P(X=x)\mathrm{P}(X=x)636\frac6{36}1036\frac{10}{36}836\frac8{36}636\frac6{36}436\frac4{36}236\frac2{36}

(b)

解法一

思路

展开

用分布表求一阶矩及二阶矩,最后把均值与方差明确区分。

答题过程

展开 E(X)= 10+16+18+16+1036=3518,E(X2)= 10+32+54+64+5036=356.\begin{align*} \mathrm{E}(X)=&\,\frac{10+16+18+16+10}{36} =\boxed{\frac{35}{18}},\\[4mm] \mathrm{E}(X^2)=&\,\frac{10+32+54+64+50}{36} =\frac{35}{6}. \end{align*}

Therefore,

Var⁡(X)= 356−(3518)2= 1890−1225324= 665324.\begin{align*} \operatorname{Var}(X) =&\,\frac{35}{6}-\biggl(\frac{35}{18}\biggr)^2\\[4mm] =&\,\frac{1890-1225}{324}\\[4mm] =&\,\boxed{\frac{665}{324}}. \end{align*}