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CIE 9709 2025 November Paper 51 Q4

A Level / CIE / S1

CIE 9709 2025 Nov Paper 51 Paper · Question 4

题目

Problem

Bag AA contains 8 red marbles and 3 blue marbles. Bag BB contains 4 red marbles and 1 blue marble.

A marble is chosen at random from bag AA. If the marble chosen is red, it is discarded. If the marble chosen is blue, it is placed in bag BB.

A marble is then chosen at random from bag BB. If the marble chosen is red, it is discarded. If the marble chosen is blue, it is placed in bag AA.

A marble is now chosen at random from bag AA.

(a) Complete the tree diagram below by entering all the remaining outcomes and probabilities.

(3)

(b) Find the probability that all three marbles chosen are the same colour.

(2)
题目中文翻译

袋 AA 中有 8 颗红色弹珠和 3 颗蓝色弹珠。袋 BB 中有 4 颗红色弹珠和 1 颗蓝色弹珠。

从袋 AA 中随机取出一颗弹珠。若取出的是红色弹珠,就将其弃去;若取出的是蓝色弹珠,就将其放入袋 BB。

接着从袋 BB 中随机取出一颗弹珠。若取出的是红色弹珠,就将其弃去;若取出的是蓝色弹珠,就将其放入袋 AA。

现在从袋 AA 中随机取出一颗弹珠。

(a) 填入其余所有结果及概率,补全下方的树状图。

(3)

(b) 求取出的三颗弹珠颜色全部相同的概率。

(2)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

(a)

解法一

思路

展开

依次更新每个袋中的红蓝数量。红珠被丢弃,蓝珠则转移到另一袋,因此最后一次从A袋取珠的概率取决于前两次的完整路径。

答题过程

展开

The completed branches are:

First choice from ASecond choice from BFinal choice from A
Red, 811\frac8{11}Red, 45\frac45Red 710\frac7{10}; Blue 310\frac3{10}
Red, 811\frac8{11}Blue, 15\frac15Red 711\frac7{11}; Blue 411\frac4{11}
Blue, 311\frac3{11}Red, 46\frac46Red 810\frac8{10}; Blue 210\frac2{10}
Blue, 311\frac3{11}Blue, 26\frac26Red 811\frac8{11}; Blue 311\frac3{11}

For example, after Red then Blue, A has lost one red marble and gained a blue marble, leaving 7 red and 4 blue.

(b)

解法一

思路

展开

三珠同色只能是红红红或蓝蓝蓝。沿树图分别相乘,再相加。

答题过程

展开 P(same colour)= 81145710+31126311= 224550+18726= 13073025.\begin{align*} \mathrm{P}(\text{same colour}) =&\,\frac8{11}\frac45\frac7{10} +\frac3{11}\frac26\frac3{11}\\[4mm] =&\,\frac{224}{550}+\frac{18}{726}\\[4mm] =&\,\boxed{\frac{1307}{3025}}. \end{align*}