题目
(a) Find the number of different arrangements of the 9 letters in the word DAFFODILS in which there is a D at each end and the two Fs are not next to each other.
(b) Find the probability that a randomly chosen arrangement of the 9 letters in the word DAFFODILS has exactly 4 letters between the two Ds.
题目中文翻译
(a) 求将单词 DAFFODILS 的 9 个字母排列成两端各有一个 D,且两个 F 不相邻的不同排列数。
(b) 随机选取单词 DAFFODILS 的 9 个字母的一种排列,求两个 D 之间恰有 4 个字母的概率。
原卷通用作答要求
Answer all questions. You should use a calculator where appropriate.
You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.
Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.
请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。
解答
(a)
解法一
思路
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固定首尾的D以后,内部7个字母中两个F相同。先算全部排列,再减去FF相邻的排列。
答题过程
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Fix a D at each end. The remaining seven letters are A, F, F, O, I, L, S, giving arrangements.
If FF is treated as one block, there are six distinct objects, giving arrangements. Hence
解法二
思路
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也可以先排五个不同字母A、O、I、L、S,再把两个F放在六个不同空隙中。
答题过程
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Arrange A, O, I, L, S in ways between the fixed Ds. These letters create six gaps, all between the two Ds.
Choose two distinct gaps and place one F in each. Thus the required number is
(b)
解法一
思路
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两个D之间恰有4个字母,位置相差5。左D有4种位置,剩下7格含两个相同的F;最后除以全部不同排列数。
答题过程
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The possible position pairs for the Ds are .
For each pair, the other seven letters have arrangements, so the number of favourable arrangements is
The total number of different arrangements is . Therefore,
解法二
思路
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另一条路线按夹在D之间的F数分类,将D及中间四字母合成块。0、1、2个F的三种情况需要分别处理相同F的排列。
答题过程
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The five letters other than D and F are A, O, I, L, S.
Treat the string D____D as one block. Count according to the number of Fs inside it:
- No F inside: choose and order four of the five distinct letters, then arrange the block, the remaining distinct letter and two identical Fs:
- One F inside: choose three of the five distinct letters and arrange them with F. The block and the three remaining distinct letters have arrangements:
- Two Fs inside: choose two of the five distinct letters, arrange the four internal letters accounting for the identical Fs, then arrange the block and the three remaining letters:
Therefore,