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CIE 9709 2022 June Paper 62 Q2

A Level / CIE / S2

CIE 9709 2022 June Paper 62 Paper · Question 2

题目

Problem

In the past, the mean height of plants of a particular species has been 2.3 m2.3\,\mathrm{m}. A random sample of 6060 plants of this species was treated with fertiliser and the mean height of these 6060 plants was found to be 2.4 m2.4\,\mathrm{m}. Assume that the standard deviation of the heights of plants treated with fertiliser is 0.4 m0.4\,\mathrm{m}.

Carry out a test at the 2.5%2.5\% significance level of whether the mean height of plants treated with fertiliser is greater than 2.3 m2.3\,\mathrm{m}.

(5)
题目中文翻译

过去,某种植物的平均高度为 2.3 m2.3\,\mathrm{m}。随机抽取该种植物 6060 株,施用肥料,测得这 6060 株植物的平均高度为 2.4 m2.4\,\mathrm{m}。假设施肥后植物高度的标准差为 0.4 m0.4\,\mathrm{m}。

在 2.5%2.5\% 的显著性水平下检验施肥后的植物平均高度是否大于 2.3 m2.3\,\mathrm{m}。

(5)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

解法一

思路

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以施肥后总体平均高度为参数作右尾检验,使用已知标准差0.4及60的样本量。

答题过程

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Let μ\mu be the population mean height of plants treated with fertiliser, in metres.

H0:μ=2.3,H1:μ>2.3.H_0:\mu=2.3,\qquad H_1:\mu>2.3.

Using the large-sample normal approximation,

z=2.4−2.30.4/60=1.93649….z=\frac{2.4-2.3}{0.4/\sqrt{60}} =1.93649\ldots.

The upper-tail 2.5% critical value is 1.961.96. Since 1.93649…<1.961.93649\ldots<1.96, we do not reject H0H_0.

There is insufficient evidence at the 2.5% significance level that the population mean height of treated plants is greater than 2.3 m.