Skip to content
CalcGospel 國際數學圖譜
返回

CIE 9709 2022 June Paper 62 Q4

A Level / CIE / S2

CIE 9709 2022 June Paper 62 Paper · Question 4

题目

Problem

The number of cars arriving at a certain road junction on a weekday morning has a Poisson distribution with mean 4.64.6 per minute. Traffic lights are installed at the junction and a council officer wishes to test at the 2%2\% significance level whether there are now fewer cars arriving. He notes the number of cars arriving during a randomly chosen 22-minute period.

(a) State suitable null and alternative hypotheses for the test.

(1)

(b) Find the critical region for the test.

(4)

The officer notes that, during a randomly chosen 22-minute period on a weekday morning, exactly 55 cars arrive at the junction.

(c) Carry out the test.

(2)

(d) State, with a reason, whether it is possible that a Type I error has been made in carrying out the test in part (c).

(1)

The number of cars arriving at another junction on a weekday morning also has a Poisson distribution with mean 4.64.6 per minute.

(e) Use a suitable approximating distribution to find the probability that more than 300300 cars will arrive at this junction in an hour.

(3)
题目中文翻译

工作日上午,到达某个路口的汽车数服从泊松分布,平均每分钟 4.64.6 辆。该路口安装了交通信号灯,一名地方议会的工作人员想在 2%2\% 的显著性水平下检验现在到达的汽车数是否减少。他随机选取一段 22 分钟的时间,记录到达的汽车数。

(a) 写出适合该检验的原假设和备择假设。

(1)

(b) 求该检验的拒绝域。

(4)

该工作人员在一个工作日的上午随机选取一段 22 分钟的时间,记录到恰好有 55 辆汽车到达路口。

(c) 进行该检验。

(2)

(d) 说明 (c) 的检验中是否可能犯了第一类错误,并给出理由。

(1)

工作日上午,到达另一个路口的汽车数也服从泊松分布,平均每分钟 4.64.6 辆。

(e) 用适当的近似分布求一小时内到达这个路口的汽车超过 300300 辆的概率。

(3)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

(a)

解法一

思路

展开

以安装交通灯后的每分钟总体平均到达数为参数,备择为减少。

答题过程

展开

Let λ\lambda be the population mean number of cars arriving per minute on weekday mornings after the traffic lights were installed.

H0:λ=4.6,H1:λ<4.6.\boxed{H_0:\lambda=4.6,\qquad H_1:\lambda<4.6}.

(b)

解法一

思路

展开

原假设下两分钟总数参数为9.2。比较相邻左尾概率与2%,找到最大的拒绝边界。

答题过程

展开

Let CC be the number arriving in two minutes. Under H0H_0, C∼Po(9.2)C\sim\mathrm{Po}(9.2).

P(C≤3)= e−9.2(1+9.2+9.222!) +e−9.29.233!= 0.0184196…<0.02.\begin{align*} \mathrm{P}(C\leq3)=&\,e^{-9.2}\bigg(1+9.2+\frac{9.2^2}{2!}\bigg)\\[4mm] &\,+e^{-9.2}\frac{9.2^3}{3!}\\[4mm] =&\,0.0184196\ldots<0.02. \end{align*}

However,

P(C≤4)= P(C≤3)+e−9.29.244!= 0.0485796…>0.02.\begin{align*} \mathrm{P}(C\leq4)=&\,\mathrm{P}(C\leq3)+e^{-9.2}\frac{9.2^4}{4!}\\[4mm] =&\,0.0485796\ldots>0.02. \end{align*}

Therefore the critical region is C≤3\boxed{C\leq3}.

(c)

解法一

思路

展开

5辆不在拒绝域,因而不拒绝原假设并给出不足证据的结论。

答题过程

展开

The observed count of 5 is outside the critical region C≤3C\leq3, so H0H_0 is not rejected. There is insufficient evidence at the 2% significance level that the population mean arrival rate has decreased.

(d)

解法一

思路

展开

第一类错误必须拒绝真实原假设;本次未拒绝。

答题过程

展开

No. A Type I error requires rejection of a true H0H_0, whereas H0H_0 was not rejected in part (c).

(e)

解法一

思路

展开

一小时总数参数为276,正态近似并将超过300修正为300.5。

答题过程

展开

For the one-hour total,

C60∼ Po(60(4.6))=Po(276)≈ N(276,276).\begin{align*} C_{60}\sim&\,\mathrm{Po}(60(4.6))=\mathrm{Po}(276)\\[4mm] \approx&\,\mathrm{N}(276,276). \end{align*}

With a continuity correction,

P(C60>300)≈ 1−Φ(300.5−276276)= 0.0701(3 s.f.).\begin{align*} \mathrm{P}(C_{60}>300)\approx&\,1-\Phi\bigg(\frac{300.5-276}{\sqrt{276}}\bigg)\\[4mm] =&\,\boxed{0.0701}\quad\text{(3 s.f.).} \end{align*}