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CIE 9709 2025 June Paper 65 Q3

A Level / CIE / S2

CIE 9709 2025 June Paper 65 Paper · Question 3

题目

Problem

Maroulla’s calculator can generate random numbers between 0.0000.000 and 0.9990.999 inclusive, correct to 33 significant figures. She plans to use her calculator to choose a sample of members from the 851851 members in her health club. She numbers the members from 11 to 851851. Then she uses her calculator to generate some random numbers. She multiplies each random number by 851851 and rounds up to the next whole number to give the number of a member in the sample. This is called a ‘member number’.

(a) Maroulla’s first random number is 0.4010.401.

Find the member number that is produced by this random number.

(1)

(b) Find all possible random numbers, correct to 33 decimal places, that would produce the following member numbers.

(i) A member number of 680680.

(1)

(ii) A member number of 850850.

(1)

(c) Explain briefly how your answers to part (b) show that Maroulla’s method does not produce a random sample.

(1)
题目中文翻译

Maroulla 的计算器能够生成介于 0.0000.000 与 0.9990.999 之间(含端点)、保留 33 位有效数字的随机数。她计划用计算器从健身俱乐部的 851851 名会员中抽取一个样本。她把会员从 11 到 851851 编号,然后用计算器生成若干随机数。她将每个随机数乘以 851851,再向上取到下一个整数,得到样本中一名会员的编号。这个编号称为“会员编号”。

(a) Maroulla 生成的第一个随机数是 0.4010.401。

求这个随机数产生的会员编号。

(1)

(b) 求能产生下列会员编号的所有可能随机数,保留 33 位小数。

(i) 会员编号为 680680。

(1)

(ii) 会员编号为 850850。

(1)

(c) 简要说明为什么你在 (b) 中的答案表明 Maroulla 的方法无法得到随机样本。

(1)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

(a)

解法一

思路

展开

先乘以人数,再向上取整。

答题过程

展开

Since 851(0.401)=341.251851(0.401)=341.251, rounding up gives member number 342\boxed{342}.

(b)(i)

解法一

思路

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向上取整规则对应左开右闭区间,在其中列出符合精度的输出。

答题过程

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For output uu to give member number 680680,

679<851u≤680,679<851u\le680,

so

679851<u≤680851.\frac{679}{851}<u\le\frac{680}{851}.

This is approximately 0.797885<u≤0.7990600.797885<u\le0.799060. The possible calculator outputs are 0.798, 0.799\boxed{0.798,\ 0.799}.

(b)(ii)

解法一

思路

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同样先解取整不等式,再检查三位小数。

答题过程

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For member number 850850,

849<851u≤850.849<851u\le850.

Thus

849851<u≤850851.\frac{849}{851}<u\le\frac{850}{851}.

The interval is approximately 0.997650<u≤0.9988250.997650<u\le0.998825, so the only output is 0.998\boxed{0.998}.

(c)

解法一

思路

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两个成员对应的等可能输出个数不同,因此选择概率不同。

答题过程

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Two outputs select member 680680, but only one selects member 850850. These outputs are equally likely, so member 680680 has twice the selection probability of member 850850. The members do not have equal chances, so the method does not produce a random sample.