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CIE 9709 2022 November Paper 61 Q5

A Level / CIE / S2

CIE 9709 2022 Nov Paper 61 Paper · Question 5

题目

Problem

A builders’ merchant sells stones of different sizes.

(a) The masses of size AA stones have standard deviation 66 grams. The mean mass of a random sample of 200200 size AA stones is 4545 grams.

Find a 95%95\% confidence interval for the population mean mass of size AA stones.

(3)

(b) The masses of size BB stones have standard deviation 1111 grams. Using a random sample of size 200200, an α%\alpha\% confidence interval for the population mean mass is found to have width 44 grams.

Find α\alpha.

(4)
题目中文翻译

一家建材商出售不同规格的石块。

(a) AA 规格石块质量的标准差为 66 克。随机抽取 200200 块 AA 规格石块,样本平均质量为 4545 克。

求 AA 规格石块的总体平均质量的一个 95%95\% 置信区间。

(3)

(b) BB 规格石块质量的标准差为 1111 克。使用一个容量为 200200 的随机样本,求得总体平均质量的一个 α%\alpha\% 置信区间,其宽度为 44 克。

求 α\alpha。

(4)
原卷通用作答要求

Answer all questions. You should use a calculator where appropriate.

You must show all necessary working clearly; no marks will be given for unsupported answers from a calculator.

Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place for angles in degrees, unless a different level of accuracy is specified in the question.

请回答所有题目。适当时应使用计算器。必须清楚展示所有必要的计算过程;仅给出计算器答案而没有过程,不予评分。除非题目另有精度要求,非精确数值答案保留 3 位有效数字,以度为单位的角度保留 1 位小数。

解答

(a)

解法一

思路

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已知总体标准差,用样本均值加减1.96倍标准误。

答题过程

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Since the random sample is large, the Central Limit Theorem gives an approximately normal sampling distribution for the sample mean. The 95% confidence interval is

45±1.966200=45±0.831558….45\pm1.96\frac6{\sqrt{200}} =45\pm0.831558\ldots.

Thus the interval for the population mean mass is

(44.2, 45.8) g(3 s.f.).\boxed{(44.2,\ 45.8)\text{ g}}\quad\text{(3 s.f.).}

(b)

解法一

思路

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区间半宽为2,用半宽反求z,再求负z至正z的中央概率并乘100。

答题过程

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Let zz be the positive critical value. Since the width is 4 g,

2z11200=4.2z\frac{11}{\sqrt{200}}=4.

Hence

z=220011=2.571297….z=\frac{2\sqrt{200}}{11}=2.571297\ldots.

Therefore

α=100(2Φ(z)−1)=98.9868…,\alpha=100\bigl(2\Phi(z)-1\bigr) =98.9868\ldots,

giving α=99.0\boxed{\alpha=99.0} (3 s.f.).