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IAL 2020 May FP1 Q4

A Level / Edexcel / FP1

IAL 2020 May Paper · Question 4

题目

Problem

4. (a) Use the standard results for r=1nr2\displaystyle\sum_{r=1}^{n} r^2 and r=1nr\displaystyle\sum_{r=1}^{n} r to show that

r=1n(2r1)2=13n(4n21)\sum_{r=1}^{n} (2r - 1)^2 = \frac{1}{3}n(4n^2 - 1)

for all positive integers nn.

(5)

(b) Hence find the exact value of the sum of the squares of the odd numbers between 200200 and 500500

(4)
题目中文翻译
  1. (a) 利用 r=1nr2\displaystyle\sum_{r=1}^{n} r^2r=1nr\displaystyle\sum_{r=1}^{n} r 的标准结果证明

r=1n(2r1)2=13n(4n21)\sum_{r=1}^{n} (2r - 1)^2 = \frac{1}{3}n(4n^2 - 1)

对所有正整数 nn 成立。

(b) 由此求 200200500500 之间所有奇数的平方和的精确值。

解答