题目
Problem
(i) A sequence of numbers u1,u2,u3,… is defined by
un+1=31(2un−1)u1=1
Prove by induction that, for n∈Z+
un=3(32)n−1
(6)
(ii) f(n)=2n+2+32n+1
Prove by induction that, for n∈Z+, f(n) is a multiple of 7
(6)
题目中文翻译
(i) 数列 u1,u2,u3,… 定义为
un+1=31(2un−1)u1=1
用数学归纳法证明:对于 n∈Z+,
un=3(32)n−1
(ii) f(n)=2n+2+32n+1
用数学归纳法证明:对于 n∈Z+,f(n) 是 7 的倍数。
解答