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IAL 2022 June FP1 Q2

A Level / Edexcel / FP1

IAL 2022 June Paper · Question 2

题目

Problem

2. f(x)=102x12x1x3x>0f(x) = 10 - 2x - \dfrac{1}{2x} - \dfrac{1}{x^3} \quad x > 0

(a) Show that the equation f(x)=0f(x) = 0 has a root α\alpha in the interval [0.4,0.5][0.4, 0.5]

(2)

(b) Determine f(x)f'(x).

(3)

(c) Using x0=0.5x_0 = 0.5 as a first approximation to α\alpha, apply the Newton-Raphson procedure once to f(x)f(x) to find a second approximation to α\alpha, giving your answer to 3 decimal places.

(2)

The equation f(x)=0f(x) = 0 has another root β\beta in the interval [4.8,4.9][4.8, 4.9]

(d) Use linear interpolation once on the interval [4.8,4.9][4.8, 4.9] to find an approximation to β\beta, giving your answer to 3 decimal places.

(2)
题目中文翻译
  1. f(x)=102x12x1x3x>0f(x) = 10 - 2x - \dfrac{1}{2x} - \dfrac{1}{x^3} \quad x > 0

(a) 证明方程 f(x)=0f(x) = 0 在区间 [0.4,0.5][0.4, 0.5] 内有一个根 α\alpha

(b) 求 f(x)f'(x)

(c) 取 x0=0.5x_0 = 0.5 作为 α\alpha 的第一个近似值,对 f(x)f(x) 应用一次 Newton-Raphson 法,求 α\alpha 的第二个近似值,答案保留 3 位小数。

方程 f(x)=0f(x) = 0 在区间 [4.8,4.9][4.8, 4.9] 内有另一个根 β\beta

(d) 在区间 [4.8,4.9][4.8, 4.9] 上使用一次线性插值,求 β\beta 的近似值,答案保留 3 位小数。

解答