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IAL 2023 Jan FP1 Q4

A Level / Edexcel / FP1

IAL 2023 Jan Paper · Question 4

题目

Problem

f(x)=118x+24x2x>0f(x) = 1 - \frac{1}{8x} + \frac{2}{4x^2} \quad x > 0

The equation f(x)=0f(x) = 0 has a single root, α\alpha, that lies in the interval [0.15,0.25][0.15, 0.25]

(a) (i) Determine f(x)f'(x)

(ii) Explain why 0.250.25 cannot be used as an initial approximation for α\alpha in the Newton-Raphson process.

(iii) Taking 0.150.15 as a first approximation to α\alpha apply the Newton-Raphson process once to f(x)f(x) to obtain a second approximation to α\alpha Give your answer to 33 decimal places.

(5)

(b) Use linear interpolation once on the interval [0.15,0.25][0.15, 0.25] to find another approximation to α\alpha Give your answer to 33 decimal places.

(3)
题目中文翻译

f(x)=118x+24x2x>0f(x) = 1 - \frac{1}{8x} + \frac{2}{4x^2} \quad x > 0

方程 f(x)=0f(x) = 0 有唯一根 α\alpha,位于区间 [0.15,0.25][0.15, 0.25] 内。

(a) (i) 确定 f(x)f'(x)

(ii) 解释为什么 0.250.25 不能作为 Newton-Raphson 法中 α\alpha 的初始近似值。

(iii) 取 0.150.15 作为 α\alpha 的第一个近似值,对 f(x)f(x) 应用一次 Newton-Raphson 法,求 α\alpha 的第二个近似值,答案保留 33 位小数。

(b) 在区间 [0.15,0.25][0.15, 0.25] 上使用一次线性插值法,求 α\alpha 的另一个近似值,答案保留 33 位小数。

解答