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IAL 2024 Jan FP1 Q7

A Level / Edexcel / FP1

IAL 2024 Jan Paper · Question 7

题目

Problem

The parabola CC has equation y2=43xy^2 = \dfrac{4}{3}x

The point P(13t2,23t)P\left(\dfrac{1}{3}t^2, \dfrac{2}{3}t\right), where t0t \neq 0, lies on CC.

(a) Use calculus to show that the normal to CC at PP has equation

3tx+3y=t3+2t3tx + 3y = t^3 + 2t

(3)

The normal to CC at the point where t=9t = 9 meets CC again at the point QQ.

(b) Determine the exact coordinates of QQ.

(4)
题目中文翻译

抛物线 CC 的方程为 y2=43xy^2 = \dfrac{4}{3}x

P(13t2,23t)P\left(\dfrac{1}{3}t^2, \dfrac{2}{3}t\right)(其中 t0t \neq 0)在 CC 上。

(a) 使用微积分证明:CC 在点 PP 处的法线方程为 3tx+3y=t3+2t3tx + 3y = t^3 + 2t

CCt=9t = 9 处的法线再次与 CC 相交于点 QQ

(b) 确定 QQ 的精确坐标。

解答