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IAL 2025 Jan FP1 Q2

A Level / Edexcel / FP1

IAL 2025 Jan Paper · Question 2

题目

Problem

f(x)=x27x4xx3x>0f(x) = x^2 - \frac{7x - 4\sqrt{x}}{x^3}\quad x > 0

(a) Show that the equation f(x)=0f(x) = 0 has a root α\alpha in the interval [0.3,0.4][0.3, 0.4]

(2)

(b) Determine f(x)f'(x).

(3)

(c) Using x0=0.3x_0 = 0.3 as a first approximation for α\alpha, apply the Newton–Raphson procedure once to f(x)f(x) to determine a second approximation for α\alpha, giving your answer to 3 decimal places.

(2)

The equation f(x)=0f(x) = 0 has another root β\beta in the interval [1.3,1.5][1.3, 1.5]

(d) Use linear interpolation once on the interval [1.3,1.5][1.3, 1.5] to determine an approximation for β\beta, giving your answer to 3 decimal places.

(2)
题目中文翻译

已知函数 f(x)=x27x4xx3x>0f(x) = x^2 - \frac{7x - 4\sqrt{x}}{x^3}\quad x > 0

(a) 证明方程 f(x)=0f(x) = 0 在区间 [0.3,0.4][0.3, 0.4] 内有一个根 α\alpha

(b) 求出 f(x)f'(x)

(c) 以 x0=0.3x_0 = 0.3 作为 α\alpha 的首次近似值,对 f(x)f(x) 应用一次 Newton–Raphson 迭代法以确定 α\alpha 的第二次近似值,结果保留 3 位小数。

方程 f(x)=0f(x) = 0 在区间 [1.3,1.5][1.3, 1.5] 内有另一个根 β\beta

(d) 在区间 [1.3,1.5][1.3, 1.5] 上应用一次线性插值法(linear interpolation)来确定 β\beta 的近似值,结果保留 3 位小数。

解答