题目
Problem
Figure 1
Figure 1 shows a sketch of the curve with polar equation
r=10cosθ+tanθ0⩽θ<2π
The point P lies on the curve where θ=3π.
The region R , shown shaded in Figure 1, is bounded by the initial line, the curve and the line OP , where O is the pole.
Use algebraic integration to show that the exact area of R is
121(aπ+b3+c)
where a , b and c are integers to be determined.
(9)
解答
解法一
思路
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区域由 θ=0、θ=3π 和曲线围成,所以直接用极坐标面积公式 21∫r2dθ。关键是把 r2 展开后改写成容易积分的形式:cos2θ=21(1+cos2θ),tan2θ=sec2θ−1。
答题过程
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The area is
Area=21∫03πr2dθ
First expand r2:
r2===(10cosθ+tanθ)2100cos2θ+20cosθtanθ+tan2θ100cos2θ+20sinθ+tan2θ
Use
cos2θ=tan2θ=21(1+cos2θ)sec2θ−1
Therefore
Area===21∫03π(100cos2θ+20sinθ+tan2θ)dθ21∫03π(50(1+cos2θ)+20sinθ+sec2θ−1)dθ21∫03π(49+50cos2θ+20sinθ+sec2θ)dθ
Integrate:
Area=21[49θ+25sin2θ−20cosθ+tanθ]03π
Substitute the limits:
Area=====21[(349π+25sin32π−20cos3π+tan3π)−(0+25sin0−20cos0+tan0)]21[(349π+2253−10+3)−(−20)]21(349π+2273+10)649π+4273+51298π+813+60
This is in the required form
121(aπ+b3+c)
where
a=98,b=81,c=60