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IAL 2021 Oct FP3 Q3

A Level / Edexcel / FP3

IAL 2021 Oct Paper · Question 3

题目

Problem

The ellipse EE has equation

x264+y236=1.\frac{x^2}{64} + \frac{y^2}{36} = 1.

The line ll is the normal to EE at the point P(8cosθ,6sinθ)P(8\cos\theta, 6\sin\theta).

(a) Using calculus, show that an equation for ll is

4xsinθ3ycosθ=14sinθcosθ.4x\sin\theta - 3y\cos\theta = 14\sin\theta\cos\theta.

The line ll meets the xx-axis at the point AA and meets the yy-axis at the point BB. The point MM is the midpoint of ABAB.

(b) Determine a Cartesian equation for the locus of MM as θ\theta varies, giving your answer in the form ax2+by2=cax^2 + by^2 = c where aa, bb and cc are integers.

(9)
题目中文翻译

椭圆 EE 的方程为

x264+y236=1\frac{x^2}{64} + \frac{y^2}{36} = 1。

直线 ll 是椭圆 EE 在点 P(8cosθ,6sinθ)P(8\cos\theta, 6\sin\theta) 处的法线。

(a) 利用微积分证明 ll 的方程为

4xsinθ3ycosθ=14sinθcosθ4x\sin\theta - 3y\cos\theta = 14\sin\theta\cos\theta。

直线 llxx 轴交于点 AA,与 yy 轴交于点 BB。 点 MMABAB 的中点。

(b) 求当 θ\theta 变化时,MM 的轨迹的笛卡尔方程,并写成 ax2+by2=cax^2 + by^2 = c 的形式,其中 aabbcc 为整数。

解答