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IAL 2022 Jan FP3 Q8

A Level / Edexcel / FP3

IAL 2022 Jan Paper · Question 8

题目

Problem

The ellipse EE has equation

x29+y24=1\frac{x^2}{9}+\frac{y^2}{4}=1

(a) Determine the eccentricity of EE

(b) Hence, for this ellipse, determine

(i) the coordinates of the foci,

(ii) the equations of the directrices.

The point PP lies on EE and has coordinates (3cosθ,2sinθ)(3\cos\theta,2\sin\theta).

The line l1l_1 is the tangent to EE at the point PP

(c) Using calculus, show that an equation for l1l_1 is

2xcosθ+3ysinθ=62x\cos\theta+3y\sin\theta=6

The line l2l_2 passes through the origin and is perpendicular to l1l_1

The line l1l_1 intersects the line l2l_2 at the point QQ

(d) Determine the coordinates of Q

(e) Show that, as θ\theta varies, the point QQ lies on the curve with equation

(x2+y2)2=αx2+βy2(x^2+y^2)^2=\alpha x^2+\beta y^2

where α\alpha and β\beta are constants to be determined.

(11)
题目中文翻译

椭圆 EE 的方程为

x29+y24=1\frac{x^2}{9}+\frac{y^2}{4}=1

(a) 求 EE 的离心率

(b) 因此,对该椭圆,求

(i) 焦点坐标,

(ii) 准线方程。

PPEE 上,坐标为 (3cosθ,2sinθ)(3\cos\theta,2\sin\theta)

直线 l1l_1EE 在点 PP 处的切线

(c) 用微积分证明 l1l_1 的方程为

2xcosθ+3ysinθ=62x\cos\theta+3y\sin\theta=6

直线 l2l_2 过原点并且垂直于 l1l_1

直线 l1l_1l2l_2 相交于点 QQ

(d) 求 QQ 的坐标

(e) 证明当 θ\theta 变化时,点 QQ 位于方程

(x2+y2)2=αx2+βy2(x^2+y^2)^2=\alpha x^2+\beta y^2

所表示的曲线上,其中 α\alphaβ\beta 为待定常数。

解答