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IAL 2023 June FP3 Q6

A Level / Edexcel / FP3

IAL 2023 June Paper · Question 6

题目

Problem

The ellipse EE has equation

x216+y29=1\frac{x^2}{16}+\frac{y^2}{9}=1

The point P(4cosθ,3sinθ)P(4\cos\theta,3\sin\theta) lies on EE.

(a) Use calculus to show that an equation of the tangent to EE at PP is

3xcosθ+4ysinθ=123x\cos\theta+4y\sin\theta=12

(b) Determine an equation for the normal to EE at PP.

The tangent to EE at PP meets the xx-axis at the point AA.

The normal to EE at PP meets the yy-axis at the point BB.

(c) Show that the locus of the midpoint of AA and BB as θ\theta varies has equation

x2(pqy2)=rx^2(p-qy^2)=r

where pp, qq and rr are integers to be determined.

(13)
题目中文翻译

椭圆 EE 的方程为

x216+y29=1\frac{x^2}{16}+\frac{y^2}{9}=1

P(4cosθ,3sinθ)P(4\cos\theta,3\sin\theta)EE 上。

(a) 用微积分证明 EE 在点 PP 处的切线方程为

3xcosθ+4ysinθ=123x\cos\theta+4y\sin\theta=12

(b) 求 EE 在点 PP 处的法线方程。

EE 在点 PP 处的切线与 xx 轴交于点 AA

EE 在点 PP 处的法线与 yy 轴交于点 BB

(c) 证明当 θ\theta 变化时,AABB 的中点的轨迹方程为

x2(pqy2)=rx^2(p-qy^2)=r

其中 ppqqrr 为待定整数。

解答