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IAL 2024 June FP3 Q9

A Level / Edexcel / FP3

IAL 2024 June Paper · Question 9

题目

Problem

The plane Π1\Pi_1 has vector equation

r=(530)+s(301)+t(122)\mathbf r= \begin{pmatrix}5\\3\\0\end{pmatrix} +s\begin{pmatrix}3\\0\\1\end{pmatrix} +t\begin{pmatrix}1\\-2\\2\end{pmatrix}

where ss and tt are scalar parameters.

(a) Determine a Cartesian equation for Π1\Pi_1

The plane Π2\Pi_2 has vector equation

r(523)=1\mathbf r\cdot\begin{pmatrix}5\\-2\\3\end{pmatrix}=1

(b) Determine a vector equation for the line of intersection of Π1\Pi_1 and Π2\Pi_2

Give your answer in the form r=a+λb\mathbf r=\mathbf a+\lambda\mathbf b, where a\mathbf a and b\mathbf b are constant vectors and λ\lambda is a scalar parameter.

The plane Π3\Pi_3 has Cartesian equation 4x3yz=04x-3y-z=0

(c) Use the answer to part (b) to determine the coordinates of the point of intersection of Π1\Pi_1, Π2\Pi_2 and Π3\Pi_3

(10)
题目中文翻译

平面 Π1\Pi_1 的向量方程为

r=(530)+s(301)+t(122)\mathbf r= \begin{pmatrix}5\\3\\0\end{pmatrix} +s\begin{pmatrix}3\\0\\1\end{pmatrix} +t\begin{pmatrix}1\\-2\\2\end{pmatrix}

其中 sstt 为标量参数。

(a) 求 Π1\Pi_1 的笛卡尔方程

平面 Π2\Pi_2 的向量方程为

r(523)=1\mathbf r\cdot\begin{pmatrix}5\\-2\\3\end{pmatrix}=1

(b) 求平面 Π1\Pi_1Π2\Pi_2 的交线的向量方程。

答案写成 r=a+λb\mathbf r=\mathbf a+\lambda\mathbf b 的形式,其中 a\mathbf ab\mathbf b 为常向量,λ\lambda 为标量参数。

平面 Π3\Pi_3 的笛卡尔方程为 4x3yz=04x-3y-z=0

(c) 利用 (b) 的答案求 Π1\Pi_1Π2\Pi_2Π3\Pi_3 的交点坐标。

解答