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P1 2019 Jan Q5

A Level / Edexcel / P1

IAL 2019 Jan Paper · Question 5

题目

Problem

Figure 2 shows a plot of part of the curve with equation y=cos⁡2xy=\cos2x with xx being measured in radians.

Figure 2

The point PP, shown on Figure 2, is a minimum point on the curve.

(a) State the coordinates of PP.

(2)

A copy of Figure 2, called Diagram 1, is shown at the top of the next page.

Diagram 1

(b) Sketch, on Diagram 1, the curve with equation y=sin⁡xy=\sin x.

(2)

(c) Hence, or otherwise, deduce the number of solutions of the equation

(i) cos⁡2x=sin⁡x\cos2x=\sin x that lie in the region 0≤x≤20π0\leq x\leq20\pi,

(ii) cos⁡2x=sin⁡x\cos2x=\sin x that lie in the region 0≤x≤21π0\leq x\leq21\pi.

(2)

解答

(a)

解法一

思路

展开

cos⁡2x\cos2x 第一次取最小值 −1-1 时,2x=π2x=\pi,所以 x=π2x=\frac\pi2。

答题过程

展开 P=(π2,−1).\begin{align*} P=\left(\frac\pi2,-1\right). \end{align*}

(b)

解法一

思路

展开

y=sin⁡xy=\sin x 经过原点,最大值为 11,最小值为 −1-1,周期为 2π2\pi。

答题过程

展开

The sketch of y=sin⁡xy=\sin x should pass through the origin, have maximum value 11, minimum value −1-1, and period 2π2\pi.

(c)

解法一

思路

展开

从一段 0≤x≤2π0\leq x\leq2\pi 的图像可数出 33 个交点。20π20\pi 是 1010 个完整周期;21π21\pi 在此基础上再多半个周期。

答题过程

展开

In 0≤x≤2π0\leq x\leq2\pi, there are 33 solutions.

For 0≤x≤20π0\leq x\leq20\pi,

20π=10(2π),\begin{align*} 20\pi=10(2\pi), \end{align*}

so the number of solutions is

10⋅3=30.\begin{align*} 10\cdot3=30. \end{align*}

For 0≤x≤21π0\leq x\leq21\pi, the extra interval adds 22 more solutions, so the number of solutions is

32.\begin{align*} 32. \end{align*}