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P1 2019 May Q2

A Level / Edexcel / P1

IAL 2019 May Paper · Question 2

题目

Problem

Answer this question showing each stage of your working.

(a) Simplify

14−22,\begin{align*} \frac{1}{4-2\sqrt2}, \end{align*}

giving your answer in the form a+b2a+b\sqrt2 where aa and bb are rational numbers.

(2)

(b) Hence, or otherwise, solve the equation

4x=22x+202,\begin{align*} 4x=2\sqrt2x+20\sqrt2, \end{align*}

giving your answer in the form p+q2p+q\sqrt2 where pp and qq are rational numbers.

(3)

解答

(a)

解法一

思路

展开

分母含有根号,用共轭式 4+224+2\sqrt2 有理化。

答题过程

展开 14−22= 14−22⋅4+224+22= 4+2216−8= 12+142.\begin{align*} \frac{1}{4-2\sqrt2} =&\,\frac{1}{4-2\sqrt2}\cdot\frac{4+2\sqrt2}{4+2\sqrt2}\\ =&\,\frac{4+2\sqrt2}{16-8}\\ =&\,\frac12+\frac14\sqrt2. \end{align*}

(b)

解法一

思路

展开

先把含 xx 的项放在同一边,再用上一问的结果处理分母。

答题过程

展开 4x= 22x+202(4−22)x= 202x= 2024−22.\begin{align*} 4x=&\,2\sqrt2x+20\sqrt2\\ (4-2\sqrt2)x=&\,20\sqrt2\\ x=&\,\frac{20\sqrt2}{4-2\sqrt2}. \end{align*}

Using part (a),

x= 202(12+142)= 102+10= 10+102.\begin{align*} x =&\,20\sqrt2\left(\frac12+\frac14\sqrt2\right)\\ =&\,10\sqrt2+10\\ =&\,10+10\sqrt2. \end{align*}