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P1 2020 Jan Q7

A Level / Edexcel / P1

IAL 2020 Jan Paper · Question 7

题目

Problem

Figure 3 shows part of the curve C1C_1 with equation y=3sin⁡xy=3\sin x, where xx is measured in degrees.

Figure 3

The point PP and the point QQ lie on C1C_1 and are shown in Figure 3.

(a) State

(i) the coordinates of PP,

(ii) the coordinates of QQ.

(3)

A different curve C2C_2 has equation y=3sin⁡x+ky=3\sin x+k, where kk is a constant.

The curve C2C_2 has a maximum yy value of 1010.

The point RR is the minimum point on C2C_2 with the smallest positive xx coordinate.

(b) State the coordinates of RR.

(2)

解答

(a)

解法一

思路

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y=3sin⁡xy=3\sin x 的最大值是 33,第一次出现在 x=90∘x=90^\circ。从图上看,QQ 是下一次与 xx 轴相交的点,对应 x=540∘x=540^\circ。

答题过程

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The maximum point shown is

P=(90∘,3).\begin{align*} P=(90^\circ,3). \end{align*}

The next intercept shown is

Q=(540∘,0).\begin{align*} Q=(540^\circ,0). \end{align*}

(b)

解法一

思路

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3sin⁡x3\sin x 的最大值是 33。如果 3sin⁡x+k3\sin x+k 的最大值是 1010,则整体上移了 77。最小值是 −3+7=4-3+7=4,最小点第一次出现在 x=270∘x=270^\circ。

答题过程

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Since the maximum value is 1010,

3+k=10⇒k=7.\begin{align*} 3+k=10 \quad\Rightarrow\quad k=7. \end{align*}

The minimum value is

−3+7=4.\begin{align*} -3+7=4. \end{align*}

The smallest positive xx coordinate of a minimum point is 270∘270^\circ, so

R=(270∘,4).\begin{align*} R=(270^\circ,4). \end{align*}