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IAL 2022 May Q2

A Level / Edexcel / P1

IAL 2022 May Paper · Question 2

题目

Problem

In the triangle ABCABC,

  • AB=21cmAB=21\,\text{cm}
  • BC=13cmBC=13\,\text{cm}
  • angle BAC=25BAC=25^\circ
  • angle ACB=xACB=x^\circ

(a) Use the sine rule to find the value of sinx\sin x^\circ, giving your answer to 4 decimal places.

(2)

Given also that ABAB is the longest side of the triangle,

(b) find the value of xx, giving your answer to 2 decimal places.

(3)

解答

(a)

解法一

思路

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ABAB 对着角 C=xC=x^\circ,边 BCBC 对着角 A=25A=25^\circ。直接用正弦定理。

答题过程

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Using the sine rule,

sinx21=sin2513.\begin{align*} \frac{\sin x^\circ}{21} =&\,\frac{\sin25^\circ}{13}. \end{align*}

Therefore

sinx=21sin2513=0.6827to 4 d.p.\begin{align*} \sin x^\circ =&\,\frac{21\sin25^\circ}{13}\\ =&\,0.6827\quad\text{to 4 d.p.} \end{align*}

(b)

解法一

思路

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sinx=0.6827\sin x=0.6827 会给出一个锐角和一个钝角。因为 ABAB 是最长边,所以它对着的角 C=xC=x^\circ 必须是最大角,因此选择钝角。

答题过程

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The acute angle with sine 0.68270.6827 is

sin1(0.6827)=43.05\begin{align*} \sin^{-1}(0.6827)=43.05^\circ\ldots \end{align*}

The other possible angle is

18043.05=136.95\begin{align*} 180^\circ-43.05^\circ\ldots =&\,136.95^\circ\ldots \end{align*}

Since ABAB is the longest side, angle ACBACB is the largest angle. Hence

x=136.95\begin{align*} x=136.95^\circ \end{align*}

to 2 decimal places.